All combination factors must be unique

  • Last Post 07 August 2021
thejtluv posted this 07 August 2021

Good Afternoon,

In walking through an older exercise for CTO Setup of a manufactured chair, getting error "All combination factors must be unique" when attempting to use the same factor type (Characteristic Value) and its associated factor value twice, in order to create a combination table using the same for ranges and associated return values. The help area explicitly states this should be possible, but doesn't seem to be the case, the way I'm doing it anyhow. See screenshots:


Attached Files

thejtluv posted this 07 August 2021

Desired end game: